Java – Generate random integers in a range

java-random-integer-in-range

In this article, we will show you three ways to generate random integers in a range.

  1. java.util.Random.nextInt
  2. Math.random
  3. java.util.Random.ints (Java 8)

1. java.util.Random

This Random().nextInt(int bound) generates a random integer from 0 (inclusive) to bound (exclusive).

1.1 Code snippet. For getRandomNumberInRange(5, 10), this will generates a random integer between 5 (inclusive) and 10 (inclusive).


	private static int getRandomNumberInRange(int min, int max) {

		if (min >= max) {
			throw new IllegalArgumentException("max must be greater than min");
		}

		Random r = new Random();
		return r.nextInt((max - min) + 1) + min;
	}

1.2 What is (max – min) + 1) + min?

Above formula will generates a random integer in a range between min (inclusive) and max (inclusive).


	//Random().nextInt(int bound) = Random integer from 0 (inclusive) to bound (exclusive)
	
	//1. nextInt(range) = nextInt(max - min)
	new Random().nextInt(5);  // [0...4] [min = 0, max = 4]
	new Random().nextInt(6);  // [0...5]
	new Random().nextInt(7);  // [0...6]
	new Random().nextInt(8);  // [0...7]
	new Random().nextInt(9);  // [0...8]
	new Random().nextInt(10); // [0...9]			
	new Random().nextInt(11); // [0...10]
	
	//2. To include the last value (max value) = (range + 1)
	new Random().nextInt(5 + 1)  // [0...5] [min = 0, max = 5]
	new Random().nextInt(6 + 1)  // [0...6]
	new Random().nextInt(7 + 1)  // [0...7]
	new Random().nextInt(8 + 1)  // [0...8]
	new Random().nextInt(9 + 1)  // [0...9]
	new Random().nextInt(10 + 1) // [0...10]			
	new Random().nextInt(11 + 1) // [0...11]
	
	//3. To define a start value (min value) in a range,
	//   For example, the range should start from 10 = (range + 1) + min
	new Random().nextInt(5 + 1)  + 10 // [0...5]  + 10 = [10...15]
	new Random().nextInt(6 + 1)  + 10 // [0...6]  + 10 = [10...16]
	new Random().nextInt(7 + 1)  + 10 // [0...7]  + 10 = [10...17]
	new Random().nextInt(8 + 1)  + 10 // [0...8]  + 10 = [10...18]
	new Random().nextInt(9 + 1)  + 10 // [0...9]  + 10 = [10...19]
	new Random().nextInt(10 + 1) + 10 // [0...10] + 10 = [10...20]
	new Random().nextInt(11 + 1) + 10 // [0...11] + 10 = [10...21]
	
	// Range = (max - min)
	// So, the final formula is ((max - min) + 1) + min
	
	//4. Test [10...30]
	// min = 10 , max = 30, range = (max - min)
	new Random().nextInt((max - min) + 1) + min
	new Random().nextInt((30 - 10) + 1) + 10
	new Random().nextInt((20) + 1) + 10
	new Random().nextInt(21) + 10    //[0...20] + 10 = [10...30]
	
	//5. Test [15...99]
	// min = 15 , max = 99, range = (max - min)
	new Random().nextInt((max - min) + 1) + min
	new Random().nextInt((99 - 15) + 1) + 15
	new Random().nextInt((84) + 1) + 15
	new Random().nextInt(85) + 15    //[0...84] + 15 = [15...99]
	
	//Done, understand?

1.3 Full examples to generate 10 random integers in a range between 5 (inclusive) and 10 (inclusive).

TestRandom.java

package com.mkyong.example.test;

import java.util.Random;

public class TestRandom {

	public static void main(String[] args) {

		for (int i = 0; i < 10; i++) {
			System.out.println(getRandomNumberInRange(5, 10));
		}

	}

	private static int getRandomNumberInRange(int min, int max) {

		if (min >= max) {
			throw new IllegalArgumentException("max must be greater than min");
		}

		Random r = new Random();
		return r.nextInt((max - min) + 1) + min;
	}

}

Output.


7
6
10
8
9
5
7
10
8
5

2. Math.random

This Math.random() gives a random double from 0.0 (inclusive) to 1.0 (exclusive).

2.1 Code snippet. Refer to 1.2, more or less it is the same formula.


	(int)(Math.random() * ((max - min) + 1)) + min

2.2 Full examples to generate 10 random integers in a range between 16 (inclusive) and 20 (inclusive).

TestRandom.java

package com.mkyong.example.test;

public class TestRandom {

	public static void main(String[] args) {

		for (int i = 0; i < 10; i++) {
			System.out.println(getRandomNumberInRange(16, 20));
		}

	}

	private static int getRandomNumberInRange(int min, int max) {

		if (min >= max) {
			throw new IllegalArgumentException("max must be greater than min");
		}

		return (int)(Math.random() * ((max - min) + 1)) + min;
	}

}

Output.


17
16
20
19
20
20
20
17
20
16
Note
The Random.nextInt(n) is more efficient than Math.random() * n, read this Oracle forum post.

3. Java 8 Random.ints

In Java 8, new methods are added in java.util.Random


	public IntStream ints(int randomNumberOrigin, int randomNumberBound)
	public IntStream ints(long streamSize, int randomNumberOrigin, int randomNumberBound) 

This Random.ints(int origin, int bound) or Random.ints(int min, int max) generates a random integer from origin (inclusive) to bound (exclusive).

3.1 Code snippet.


	private static int getRandomNumberInRange(int min, int max) {
	
		Random r = new Random();
		return r.ints(min, (max + 1)).findFirst().getAsInt();

	}

3.2 Full examples to generate 10 random integers in a range between 33 (inclusive) and 38 (inclusive).

TestRandom.java

package com.mkyong.form.test;

import java.util.Random;

public class TestRandom {

	public static void main(String[] args) {

		for (int i = 0; i < 10; i++) {
			System.out.println(getRandomNumberInRange(33, 38));
		}

	}

	private static int getRandomNumberInRange(int min, int max) {
	
		Random r = new Random();
		return r.ints(min, (max + 1)).limit(1).findFirst().getAsInt();
		
	}
	
}

Output.


34
35
37
33
38
37
34
35
36
37

3.3 Extra, for self-reference.

Generates random integers in a range between 33 (inclusive) and 38 (exclusive), with stream size of 10. And print out the items with forEach.


	//Java 8 only
	new Random().ints(10, 33, 38).forEach(System.out::println);

Output.


34
37
37
34
34
35
36
33
37
34

References

  1. java.util.Random JavaDoc
  2. java.lang.Math JavaDoc
  3. Oracle forum : Random Number Generation
  4. Generating weighed random numbers in JavaScript

About the Author

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mkyong
Founder of Mkyong.com, love Java and open source stuff. Follow him on Twitter, or befriend him on Facebook or Google Plus. If you like my tutorials, consider make a donation to these charities.

Comments

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Smithf203
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Smithf203

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sai kiran chary
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sai kiran chary

Thanks, Worked to me. Looks precise.

BPC
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BPC
This code is the easiest way to return 10 random numbers between 1 and 99. I took all your ideas and came up with this brief but effective code. Just change the values of 99,1,1 to your min and max to get your #s. If you use 99 as your max, randomly 99 + 1 will make the code generate 100, so if you really want max of 99, use 98 in this code. :D * @author balcopc */ import java.util.Random; public class RandomNumberProj { public static void main(String[] args) { System.out.println(“Random Numbers: “); //print ten random numbers between 1… Read more »
Aisht
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Aisht

Why do we use limit(1) in below snippet? Using only findFirst() should return single random integer, isn’t it?
r.ints(min, (max + 1)).limit(1).findFirst().getAsInt()