How to read UTF-8 XML file in Java – (SAX Parser)
Problem
In previous SAX example, it is working fine to parse a plain text (ANSI) XML file, if some special UTF-8 words inside a XML file, it will encounter the “MalformedByteSequenceException” UTF-8 exception.
Solution
1. Create a XML file
This is a xml file which contain a special UTF-8 characters “§” (press Alt+789)
<?xml version="1.0"?> <company> <staff> <firstname>yong</firstname> <lastname>mook kim</lastname> <nickname>§</nickname> <salary>100000</salary> </staff> </company>
If you used normal SAX’s way to parse it, you will encounter this “Invalid byte 1 of 1-byte UTF-8 sequence” error.
2. Create a Java File
This is normal SAX’s way, does not support UTF-8.
saxParser.parse("c:\\file.xml", handler);
Firstly, you have make sure the file is UTF-8 encoded, and override the SAX’s input source.
File file = new File("c:\\file-utf.xml"); InputStream inputStream= new FileInputStream(file); Reader reader = new InputStreamReader(inputStream,"UTF-8"); InputSource is = new InputSource(reader); is.setEncoding("UTF-8"); saxParser.parse(is, handler);
Full example…
package com.mkyong.test; import java.io.File; import java.io.FileInputStream; import java.io.InputStream; import java.io.InputStreamReader; import java.io.Reader; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.InputSource; import org.xml.sax.SAXException; import org.xml.sax.helpers.DefaultHandler; public class ReadXMLUTF8FileSAX { public static void main( String[] args ) { try { SAXParserFactory factory = SAXParserFactory.newInstance(); SAXParser saxParser = factory.newSAXParser(); DefaultHandler handler = new DefaultHandler() { boolean bfname = false; boolean blname = false; boolean bnname = false; boolean bsalary = false; public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException { System.out.println("Start Element :" + qName); if (qName.equalsIgnoreCase("FIRSTNAME")) { bfname = true; } if (qName.equalsIgnoreCase("LASTNAME")) { blname = true; } if (qName.equalsIgnoreCase("NICKNAME")) { bnname = true; } if (qName.equalsIgnoreCase("SALARY")) { bsalary = true; } } public void endElement(String uri, String localName, String qName) throws SAXException { System.out.println("End Element :" + qName); } public void characters(char ch[], int start, int length) throws SAXException { System.out.println(new String(ch, start, length)); if (bfname) { System.out.println("First Name : " + new String(ch, start, length)); bfname = false; } if (blname) { System.out.println("Last Name : " + new String(ch, start, length)); blname = false; } if (bnname) { System.out.println("Nick Name : " + new String(ch, start, length)); bnname = false; } if (bsalary) { System.out.println("Salary : " + new String(ch, start, length)); bsalary = false; } } }; File file = new File("c:\\file.xml"); InputStream inputStream= new FileInputStream(file); Reader reader = new InputStreamReader(inputStream,"UTF-8"); InputSource is = new InputSource(reader); is.setEncoding("UTF-8"); saxParser.parse(is, handler); } catch (Exception e) { e.printStackTrace(); } } }
You have to override the SAX’s input source in order to parse XML file which contains Unicode character.



[...] Full examples can be find here – how do read UTF-8 XML file with SAX parser [...]
[...] This example may encounter some exceptions for UTF-8 XML file, please read this article about how to readthe XML UTF-8 file in SAX [...]